2sin^2x-4cosx-1=0

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Solution for 2sin^2x-4cosx-1=0 equation:


Simplifying
2sin2x + -4cosx + -1 = 0

Reorder the terms:
-1 + -4cosx + 2in2sx = 0

Solving
-1 + -4cosx + 2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + -4cosx + 1 + 2in2sx = 0 + 1

Reorder the terms:
-1 + 1 + -4cosx + 2in2sx = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -4cosx + 2in2sx = 0 + 1
-4cosx + 2in2sx = 0 + 1

Combine like terms: 0 + 1 = 1
-4cosx + 2in2sx = 1

Add '-2in2sx' to each side of the equation.
-4cosx + 2in2sx + -2in2sx = 1 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
-4cosx + 0 = 1 + -2in2sx
-4cosx = 1 + -2in2sx

Divide each side by '-4osx'.
c = -0.25o-1s-1x-1 + 0.5in2o-1

Simplifying
c = -0.25o-1s-1x-1 + 0.5in2o-1

Reorder the terms:
c = 0.5in2o-1 + -0.25o-1s-1x-1

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